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Explain why maximum current reading for 2 capacitors placed in series within a circuit differs from...

Explain why maximum current reading for 2 capacitors placed in series within a circuit differs from what is calculated I= Q/s.

Data collected for the initial maximum current is 122.1mA

Calculated current in the circuit is 8.71x10^-3 A

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Answer #1

The reading for 2 capacitors connected in series within a circuit actually differs from what is calculated by I = Q/s because in the equation I = Q/s , Q is the charge flowing , Ultima this equation is the rate of flow of charges . But the Q in the capacitors is not the charges flowing , but capacitors are actually storing charges and this storing of charges is not uniform in capacitors.

The charges stored in the capacitor is according to the formula,

Where R is the equivalent resistance of circuit.

C is the equivalent capacitance of circuit.

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