A 116 g insulated aluminum cup at 15
We need to find the final temperature of the system. Assuming no
losses, the cup and water will end up at the final temperature
T?
Specific Heat from link
C_aluminum = 0.215
C_water = 1.00
Q_cup + Q_water = 0
M_cup C_cup ?T_cup + M_water C_water ?T_water = 0
116g * 0.215 * ?T_cup + 140g * 1 * ?T_water = 0
24.94 ?T_cup + 140 ?T_water = 0
24.94 (T? - T?_cup) + 140 (T? - T?_water) = 0
24.94 T? - 24.94 T?_cup + 140 T? - 140 T?_water = 0
164.94 T? = 24.94 T?_cup + 140 T?_water
T? = (24.94 T?_cup + 140 T?_water)/164.94
= (24.94 * 15
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