Question

A 116 g insulated aluminum cup at 15

A 116 g insulated aluminum cup at 15

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Answer #1

We need to find the final temperature of the system. Assuming no losses, the cup and water will end up at the final temperature T?

Specific Heat from link
C_aluminum = 0.215
C_water = 1.00

Q_cup + Q_water = 0
M_cup C_cup ?T_cup + M_water C_water ?T_water = 0
116g * 0.215 * ?T_cup + 140g * 1 * ?T_water = 0
24.94 ?T_cup + 140 ?T_water = 0
24.94 (T? - T?_cup) + 140 (T? - T?_water) = 0
24.94 T? - 24.94 T?_cup + 140 T? - 140 T?_water = 0
164.94 T? = 24.94 T?_cup + 140 T?_water

T? = (24.94 T?_cup + 140 T?_water)/164.94
= (24.94 * 15

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