Question

I ONLY NEED PART C ANSWERED ALL OTHERS ARE CORRECT PLEASE WRITE ANSWER AS THE CORRECT DECIMAL NO SCIENTIFIC NOTATION

A 2.00-g particle moving at 5.40 m/s makes a perfectly elastic head-on collision with a resting 1.00-g object. (Assume the 2.00-g particle is moving in the positive direction before the collision. Indicate the direction with the sign of your answer.) (a) Find the velocity of each particle after the collision.

2.00-g particle=1.8 m/s

1.00-g particle=7.2 m/s

(b) Find the velocity of each particle after the collision if the stationary particle has a mass of 10.0 g.

2.00-g particle=-3.6 m/s

10.0-g particle=1.8 m/s

(c) Find the final kinetic energy of the incident 2.00-g particle in the situations described in parts (a) and (b).

KE in part (a) =

KE in part (b)=

hint: Use the final velocity you calculated for the 2.0-g particle in part (b) to find its final kinetic energy.

Answer 1

Since you have written that you have already solved Part (a) and Part (b) of the problem so I am assuming that the answers mentioned by you are correct.

Part (c) -

Kinetic Energy of 2.0 g particle after the collision in Part (a) -

KE = (1/2)*m*v^2

m = 2.0 g = 2 x 10^-3 kg

v = 1.8 m/s

So, KE = 0.5x2 x 10^-3 x 1.8^2 = 3.24 x 10^-3 J

Like wise, Kinetic Energy of 2.0 g particle after the collision in Part (b) -

KE = 0.5x2 x 10^-3 x (-3.6)^2 = 12.96 x 10^-3 J = 1.296 x 10^-2 J.