Question

A fisherman's scale stretches 3.5 cmcm when a 2.1 kgkg fish hangs from it. |
Part A What is the spring stiffness constant? Express your answer to two significant figures and include the appropriate units. Part B What will be the amplitude of vibration if the fish is pulled down 3.3 cmcm more and released so that it vibrates up and down? |

Answer #1

Stretch in the spring is x=3.5cm=0.035m

Mass of the fish is m=3.2kg

When fish hangs from the scale, the weight of the fish is balanced by spring force.

where k is the spring stiffness constant, g is the gravitational acceleration.

In two significant figures

**Part B**

When the spring balances the fish, the stretched spring is the new equilibrium position. If the fish is pulled down more, the fish will oscillate up and down about the new equilibrium position.

The spring is stretched 3.3cm more and released. The fish will
oscillate up and down with **amplitude 3.3cm** about
the new equilibrium position.

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