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A force of 720 newtons stretches a spring 4 meters. A mass of 5 kg is...

A force of 720 newtons stretches a spring 4 meters. A mass of 5 kg is attached to the end of the spring and is released from a position .5 meters below the equilibrium position with a downward velocity of 8 meters per second. What is the equation of motion?

Please solve using Differential equations

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