Question

An object is 11.5 cm from a 3.20-diopter lens. How far from the lens is the...

An object is 11.5 cm from a 3.20-diopter lens. How far from the lens is the image located?

I found the focal length using the refractive power given, and then used the thin lens equation to find di but I had no luck.

Homework Answers

Answer #1

Here optical power = 3.20 diopter

So, focal length of the lens, f = 1/3.20 = 0.3125 m = 31.25 cm

Object distance u = 11.5 cm

image distance v = ?

use the thin lens formula -

1 / u + 1/ v = 1/f

put the values -

1 / 11.5 + 1 / v = 1 / 31.25

=> 1 / v = 1 / 31.25 - 1 / 11.25

=> 1 / v = - 0.0569

=> v = -17.58 cm

So, the image is located at a distance of 17.58 cm from the lens.

The negative sign shows that location of the image is towards the left of the lens, means in the same side as the object.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
How far from the second lens will the final image be located for two convex lens...
How far from the second lens will the final image be located for two convex lens system if the object is 64 cm from the first lens the lenses are separated by 86 cm and the focal length of both lenses is 22 cm? Equation: Answer:
Two thin lenses with a focal length of magnitude 11.5 cm, the first diverging and the...
Two thin lenses with a focal length of magnitude 11.5 cm, the first diverging and the second converging, are located 8.62 cm apart. An object 1.90 mm tall is placed 19.2 cm to the left of the first (diverging) lens. A. How far from the first lens is the final image formed? B. Is the final image virtual or real? C. What is the height of the final image? D. Is it upright or inverted?
A lens has a focal length of 15 cm. An object is located 8 cm from...
A lens has a focal length of 15 cm. An object is located 8 cm from the surface of the lens. a. Calculate how far the image is from the lens. b. Tell whether the image is real or virtual. c. Calculate the magnification of the image (state whether the image is erect or inverted).
An object is placed 4949 cm to the left of a converging lens of focal length...
An object is placed 4949 cm to the left of a converging lens of focal length 1717 cm. A diverging lens of focal length −20−20 cm is located 1717 cm to the right of the first lens. (Consider the lenses as thin lenses). a) Where is the final image with respect to the second lens?
A 1.1 cm -tall object is located 25 cm to the left of a converging lens...
A 1.1 cm -tall object is located 25 cm to the left of a converging lens with focal length 20 cm . A 1.1 cm -tall object is located 25 cm to the left of a converging lens with focal length 20 cm . (correct answer: 100cm) I just need this answer: Determine the height of the image formed by the lens (in cm).
An object of size 4.0 cm is located 14 cm to the left of a thin...
An object of size 4.0 cm is located 14 cm to the left of a thin biconvex lens with a focal length of +6.5 cm. A second, thin biconcave lens is located 35 cm to the right of the first lens and has a focal length of -6.5 cm. Object and lenses are aligned on a common optical axis. (a) Sketch the resulting final image by using principal rays. (b) Is the final image real or virtual, erect or inverted?...
A converging lens, which has a focal length equal to 8.4 cm, is separated by 30.5...
A converging lens, which has a focal length equal to 8.4 cm, is separated by 30.5 cm from a second lens. The second lens is a diverging lens that has a focal length equal to -13.7 cm. An object is 16.8 cm to the left of the first lens. (a) Find the position of the final image using both a ray diagram and the thin-lens equation. __________cm to the right of the object (b) Is the final image real or...
Q2. Lenses and the Eye An object O is positioned 3.5 m from a lens of...
Q2. Lenses and the Eye An object O is positioned 3.5 m from a lens of focal length f = -1.5 m as shown: Copy the diagram and draw in: the path of a parallel ray from the top of the object through the lens; the path of a ray through the centre of the lens; and hence the location of the image. Calculate the image distance di from the lens. Mark this distance on the diagram in a). A...
A. The human eye 1. Whenever a normal eye forms an image, the image distance will...
A. The human eye 1. Whenever a normal eye forms an image, the image distance will always equal the distance from the cornea and eye lens to the retina (~25 mm), regardless of how far away the object is located. Explain why the image distance cannot change. 2. If the image distance must change, then what intrinsic property of the eye lens must change in order for the eye to focus on objects at different distances? Hint: read the Introduction....
A converging lens has a focal length of 21.5 cm. (a) Locate the object if a...
A converging lens has a focal length of 21.5 cm. (a) Locate the object if a real image is located at a distance from the lens of 107.5 cm. distance cm location (b) Locate the object if a real image is located at a distance from the lens of 129.0 cm. distance cm location (c) Locate the object if a virtual image is located at a distance from the lens of -107.5 cm. distance cm location (d) Locate the object...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT