Question

he equation of motion of a simple harmonic oscillator is given by x(t) = (7.4 cm)cos(12πt)...

he equation of motion of a simple harmonic oscillator is given by x(t) = (7.4 cm)cos(12πt) − (4.2 cm)sin(12πt), where t is in seconds.Find the amplitude. m (b) Determine the period. s (c) Determine the initial phase. °

Homework Answers

Answer #1

Initial phase = 2.087 radian = 2.087×180/π = 119.58°

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