Calculate the molar volume of ammonia gas at 273K and 1 bar using the van der Waals equation of state.
(a) First, use the critical point data Tc = 406K and Pc = 113 bar to obtain the van der Waals parameters a and b.
(b) Next use the following iterative algorithm to estimate the molar volume: (1) Re‐write the vdW EOS in the form Vm = b + RT/(P+a/Vm2), (2) Using a guess for Vm on right hand side obtain a new value of Vm (left hand side). (3) Repeat this process until Vm is converged to a few decimal places.
(a)
Given that,
Tc = 406K
Critical point temperature is,
Tc = 8a / 27Rb
406 = 8a / 27*8.314*b
a / b = 11392.9 .......(1)
Given that, Pc = 113 bar = 113*10^5 Pa
Critical point pressure is,
Pc = a / 27b^2
113*10^5 = a / 27b^2
a / b^2 =3.051*10^8 .......(2)
From equation (1) and (2)
(a / b) / b = 3.051*10^8
11392.9 / b = 3.051*10^8
b = 3.73*10^(-5) m^3 / mol
a = 0.4254 Pa*m^6 / mol^2
(b)
At T = 273 K , P = 1 bar = 10^5 Pa
from ideal gas equation,
PV = nRT
ldeal molar volume of ammonia gas,
Vm = RT / P
Vm = 8.314*273 / 10^5 = 0.0227 m^3 / mol
From Vm = b + RT / (P+a / Vm2)
By putting values and calculating,
Vm = 0.0225 m^3 / mol
so, LHS = 0.0227
RHS = 0.0225
we will choose a lower molar volume
Hence, take LHS = RHS
molar volume of ammonia gas,
Vm = 0.0225 m^3 / mol
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