Question

The absolute pressure in your car tires is 3.6 × 105 Pa at a temperature of 35.0°C when you drive it onto a ferry boat to Alaska.

What is the absolute pressure of the tires, in pascals, later when the temperature has dropped to -40.0°C? Assume the volume of each tire does not change.

Answer 1

given data

P_a= 3.6x10⁵ Pa

P _atm = 1.013x10⁵ Pa

P₁= P_a+P _atm =3.6x10⁵ Pa+ 1.013x10⁵ Pa = 4.613x10⁵ Pa

P₁= 4.613x10⁵ Pa

T₁= 35.0°C =273.15k+35k = 308.15k

T₁= 308.15 K

T₂= - 40.0°C = 273.15k-40k = 233.15 K

T₂ = 233.15 K

we know that

( P₁V₁/T₁ )=( P₂V₂/T₂ )

at constant volume

V₁=V₂

then

( P₁/T₁ )=( P₂/T₂ )

P₂ = ( P₁T₂ / T₁ )

plugging the values in the formula

P₂ = (( 4.613x10⁵ Pa)*( 233.15 K)/(308.15 K)

P₂ =3.49x10⁵ Pa

answer is = 3.49x10⁵ Pa

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