Question

The density of an object is about 400 kg/m3, and the density of water is about 1000 kg/m3. A cubic block of the object one meter on a side floats in water. Assuming that the lowest square face of the cube is horizontal, the height of the block above the water line is

0.9 m.

0.8 m.

0.5 m.

0.6 m.

0.1 m.

Answer 1

(P1)The density of an object = 400 kg/m3,

(Pw)the density of water = 1000 kg/m3

(a)object height = 1 meter

Height above water = a-h

Here when we flow archimedes principle we will get that, weight of the cube inside the water will be equal to the volume of the water displaced by it.

So that when we mathematically apply it we will get,

P1×g×a^3 = Pw × g× a^2× (a-h)

Here ,

P1 = density of

Form here we will get,

the height of the block above the water line h will be given as,

h = a(1- P1/PW)

Now on inserting the values we will get,

h = 1× (1-400/1000) = 0.6 m

Hence

the height of the block above the water line is

(0.6 m.)

Which is our required answer.