Question

At time t = 0 s, a puck is sliding on a horizontal table with a velocity 3.00 m/s, 65 above the +x axis. As the puck slides, a constant acceleration acts on it that has the following components: ax = -0.460 m/s2 and ay = -0980 m/s2. What is the velocity of the puck at time t = 1.50 s?

a 1.83 m/s, 62 degrees b. 2.04 m/s, 71.3 degrees c. 1.06 m/s, 58.7 degrees d. 2.20 m/s, 55.0 degrees e. 1.38 m/s, 65.2 degrees

Answer 1

Let us calculate final x velocity

u_x = 3 cos65 = 1.27

v_x = u_x + a_xt

v_x = 1.27 + (-0.460)(1.5)

v_x = 0.58 m/s

Let us calculate final y velocity

u_y = 3 sin 65 = 2.72 m/s

v_y = u_y + a_yt

v_y = 2.72 + (-0.980)(1.5)

v_y = 1.25 m/s

The velcoity magnitude will be

v = 1.38 m/s

The angle will be given by