Question

At time t = 0 s, a puck is sliding on a horizontal table with a velocity 3.00 m/s, 65 above the +x axis. As the puck slides, a constant acceleration acts on it that has the following components: ax = -0.460 m/s2 and ay = -0980 m/s2. What is the velocity of the puck at time t = 1.50 s?

a 1.83 m/s, 62 degrees b. 2.04 m/s, 71.3 degrees c. 1.06 m/s, 58.7 degrees d. 2.20 m/s, 55.0 degrees e. 1.38 m/s, 65.2 degrees

Answer #1

Let us calculate final x velocity

u_{x} = 3 cos65 = 1.27

v_{x} = u_{x} + a_{x}t

v_{x} = 1.27 + (-0.460)(1.5)

v_{x} = 0.58 m/s

Let us calculate final y velocity

u_{y} = 3 sin 65 = 2.72 m/s

v_{y} = u_{y} + a_{y}t

v_{y} = 2.72 + (-0.980)(1.5)

v_{y} = 1.25 m/s

The velcoity magnitude will be

v = 1.38 m/s

The angle will be given by

at
time t=0 s, an object is moving on a horizontal plane with a
velocity v0x=1.5 m/s , v0y=3.5 m/s. as the object slides, a
constant acceleration acts on it that has the following components:
ax=-2.3 m/s^2 and ay=4 m/s^2 . determine the magnitude of the
displacement of the object after 2s

Starting at t = 0 s , a horizontal net force
F? =( 0.290 N/s )ti^+(-0.460 N/s2
)t2j^ is applied to a box that has an initial
momentum p? = ( -3.05 kg?m/s )i^+( 4.00 kg?m/s
)j .What is the momentum of the box at t = 2.10 s
?

computer model displays the motion of a particle on a coordinate
system in real time. At time t = 0, the particle is at the origin
of the coordinate system and has velocity components vx = 0 and vy
= 5.2 m/s. The particle has acceleration components of ax = −4.4
m/s2 and ay = 0. (a) What are the x and y positions of the particle
at t = 6.0 s? x = m y = m (b) What...

At a time t = 2.90 s , a point on the rim of a wheel
with a radius of 0.180 m has a tangential speed of 55.0 m/s as the
wheel slows down with a tangential acceleration of constant
magnitude 10.8 m/s^2 .
A) Calculate the wheel's constant angular acceleration.
B) Calculate the angular velocity at t = 2.90 s .
C) Calculate the angular velocity at t=0.
D) Through what angle did the wheel turn between t=0
and...

At a time t = 3.10 s , a point on the rim of a wheel
with a radius of 0.210 m has a tangential speed of 51.0 m/s as the
wheel slows down with a tangential acceleration of constant
magnitude 10.6 m/s2 .
Calculate the wheel's constant angular
acceleration. rad/s^2
Calculate the angular velocity at t = 3.10 s. rad/s
Calculate the angular velocity at t=0. rad/s
Through what angle did the wheel turn between t=0 and
t = 3.10...

Sally is driving along a straight highway. At t = 0, when she is
moving in the +x direction at 10 m/s, she passes a signpost at x =
50 m. Her acceleration as a function of time is ax = 2.0 m/s2 –
(0.10 m/s3)t . (a) Find her velocity and position x as a function
of time. (b) When is her velocity greatest? (c) What is the maximum
velocity? (d) Where is the car when it reaches that...

A 0.85 kg block slides 3.3 m across a frictionless,
horizontal table at 2.2 m/s, moving left. Once the block hits the
spring, it sticks, compressing the spring 70 cm before the block
stops and reverses direction. The block then continues to bounce
back and forth, still attached to the spring. The spring constant
is 8.4 N/m. Ignore air resistance.
(b) [3 points] Plot the velocity of the block as a
function of time, with t = 0 when the...

Kinematics Examples:
A) A cat has a time dependent position given
by
x(t) = 4.50 m + (3.20 m/s^2) t^2 - (1.75 m/s^3)
t^3
Find Velocity as function of time?
Find acceleration as a function of time?
Find the position velocity, and acceleration of the
cat at t = 3.00 s?
Find average velocity and average acceleration for the
1st 3.00s?
Find the position of the cat when it first changes
direction?
B) A robot starts at X0 = 4.00m...

A speedboat starts from rest at t = 0 s, and speeds up with a
constant acceleration of 4.01 m/s2 for 6.00 s. Then it continues
with a uniform speed for another 6.00 s. Finally, it slows down
with a constant acceleration of −3.41 m/s2 . In your written work,
include the velocity vs. time and acceleration vs. time graphs for
this motion. The numerical values on the graphs are required.
(a) How long does it take for the speedboat...

At time t=0 a grinding wheel has an angular velocity of
26.0 rad/s . It has a constant angular acceleration of 33.0 rad/s2
until a circuit breaker trips at time t = 2.40 s . From
then on, the wheel turns through an angle of 431 rad as it coasts
to a stop at constant angular deceleration.
A) At what time does the wheel stop?
B) What was the wheel's angular acceleration as it slowed
down?

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 43 seconds ago

asked 43 seconds ago

asked 5 minutes ago

asked 9 minutes ago

asked 9 minutes ago

asked 15 minutes ago

asked 20 minutes ago

asked 22 minutes ago

asked 27 minutes ago

asked 28 minutes ago

asked 34 minutes ago

asked 45 minutes ago