Question

Compute the change in average kinetic energy of argon molecules
if at constant volume the gas is added the amount of heat
Q_{v} = 3516 J. The mass of argon is m = 200g &
M_{AR}=40kg.kmol^{-1}.

Answer #2

Answer :

Change in average kinetic energy = 3/2 KT

specific heat of argon at constant volume = 0.3122 kJ/kg K

Heat added = 3516 J = 3.516 KJ

mass of argon is m = 200g = 0.2 Kg

Molecular weight of Argon = 40kg.kmol^{-1}.

Heat = mC_{v}T

3.516 KJ = (0.2 Kg) (0.3122 kJ/kg K) T

T = 56.31 K

Change in average kinetic energy = 3/2 KT

where K is boltzmann constant = **1.3807** x 10
^{-}^{23} joule s per kelvin (J. K
^{-}^{1} )

K.E = 3/2 x
**1.3807** x 10 ^{-}^{23} x 56.31

K.E. = 1.166 x
10^{-21} J

answered by: anonymous

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