Question

density of water= 1000 kg/m^3 Evaporation rate: 0.103 mm/Hr Area: 1.1426 m^2 Volume change: 10 gallons...

density of water= 1000 kg/m^3 Evaporation rate: 0.103 mm/Hr Area: 1.1426 m^2 Volume change: 10 gallons to 9.25 gallons (24 hour) Calculate the flux of latent heat from the water in the pan to the atmosphere (W m^-2).

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Answer #1

Given data
density of water=1000 kg/m^3,

evaporation rate:0.103 mm/hr,

area:1.1426 m^2.

volume change:10 gallons to 9.25 gallons,

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