Question

A brick is dropped from the roof of a tall building. After it has been falling for a few seconds, it falls 35.0 m in a 1.00-s time interval.

What distance will it fall during the next 1.00 s? Ignore air resistance.

Express your answer with the appropriate units.

Answer 1

we know that distance covered in t time is given by:

h(t) = U*t + g*t^2/2

U = 0

h(t) = g*t^2/2

Given that after few seconds brick drops 35 m in 1 sec interval

Suppose interval is from T to (T + 1), then

H(T + 1) - H(T) = g*(T + 1)^2/2 - gT^2/2

35 = g*(2T + 1)/2

for next second interval from (T + 1) to (T + 2)

H(T + 2) - H(T + 1) = g*(T+2)^2/2 - g*(T + 1)^2/2

H(T + 2) - H(T + 1) = g*(2T + 3)/2

H(T + 2) - H(T + 1) = g*(2T + 1)/2 + g

from first interval we know g*(2T + 1)/2 = 35 m

H(T + 2) - H(T + 1) = 35 + 9.81

H(T + 2) - H(T + 1) = 44.81 m