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The position of a 48 g oscillating mass is given by x(t)=(1.7cm)cos11t, where t is in...

The position of a 48 g oscillating mass is given by x(t)=(1.7cm)cos11t, where t is in seconds.

Determine the velocity at t = 0.42 s .

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Answer #1

given position x=1.7cm cos11t

now for the velocity , v=dx/dt

                                     v=-11(1.7cm) sin11t

                                     v=18.6 cm/s

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