Question

A uniform electric field of magnitude 364 N/C pointing in the
positive *x*-direction acts on an electron, which is
initially at rest. The electron has moved 3.00 cm.

(a) What is the work done by the field on the electron?

(b) What is the change in potential energy associated with the electron?

(c) What is the velocity of the electron? Magnitude (m/s) ? Direction (+x, -x, -y, +y)?

Answer #1

A proton is acted on by an uniform electric field of magnitude
443 N/C pointing in the negative x direction. The particle
is initially at rest.
(a) In what direction will the charge move?
---Select--- +x direction ?x direction +y direction ?y direction +z
direction ?z direction
(b) Determine the work done by the electric field when the particle
has moved through a distance of 3.15 cm from its initial
position.
J
(c) Determine the change in electric potential energy...

A proton is acted on by an uniform electric field of magnitude
313 N/C pointing in the negative y direction. The particle is
initially at rest. (a) In what direction will the charge move? (b)
Determine the work done by the electric field when the particle has
moved through a distance of 2.45 cm from its initial position. J
(c) Determine the change in electric potential energy of the
charged particle. J (d) Determine the speed of the charged
particle....

A proton is acted on by an uniform electric field of magnitude
193 N/C pointing in the negative z direction. The particle is
initially at rest.
(a) In what direction will the charge move?
(b) Determine the work done by the electric field when the
particle has moved through a distance of 2.65 cm from its initial
position. ____J
(c) Determine the change in electric potential energy of the
charged particle. _____J
(d) Determine the speed of the charged particle.

A uniform electric field of magnitude 247 V/m is
directed in the positive x direction. A +14.2 μC
charge moves from the origin to the point (x, y)
= (22.4 cm, 46.7 cm). What was the change in the
potential energy of this charge?
Through what potential difference did the charge move?

A beam of electrons is shot into a uniform downward electric
field of magnitude 1.10 103 N/C. The electrons have an initial
velocity of 1.01 107 m/s, directed horizontally. The field acts
over a small region, 5.00 cm in the horizontal direction. (a) Find
the magnitude and direction of the electric force exerted on each
electron. (b) How does the gravitational force on an electron
compare with the electric force? (c) How far has each electron
moved in the vertical...

A uniform electric field of magnitude 267 V/m is
directed in the negative x direction. A -13.3 ?C
charge moves from the origin to the point (x, y)
= (17.8 cm, 48.2 cm).
a.) What was the change in the potential energy of this
charge?
b.) Through what potential difference did the charge move?

QUESTION When an electron is released from rest in a constant
electric field, how does the electric potential energy associated
with the electron, and the kinetic energy of the electron, change
with time? (Select all that apply.)
options:The electric potential energy becomes more negative.The
electric potential energy becomes more positive.The kinetic energy
becomes more negative.The kinetic energy stays the same.The
electric potential energy stays the same.The kinetic energy becomes
more positive.
Use the worked example above to help you solve...

A uniform electric field of 2.0×105 N/C is oriented in the
negative x direction. How much work must be done to move an
electron 3.0 m in the positive x direction, if it begins and ends
at rest?

A uniform electric field has magnitude E and is
directed in the negative x direction. The potential
difference between point a (at x= 0.70m ) and
point b (at x= 0.95m ) is 300V.
Part A
Which point, a or b, is at the higher
potential?
Part B
Calculate the value of E.
Express your answer using two significant figures.
Part C
A negative point charge q=?0.200?C is moved
from b to a. Calculate the work done on the point...

An electron is traveling through a uniform electric
field. The constant electric field is given by . At t = 0, the
electron is at (0, 0) and traveling in the positive z direction
with a speed of 5 m/s. a) What is its position 5.0 s later? b) What
is the magnitude and direction of the particle's velocity at 5.0
s?
EDIT:
Oops!
E = (-3.00 x 10^-11 N/C)i - (2.00 x 10^-11 N/C) j + (1.00 x
10^-11...

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