Question

For a moving particle which has a constant acceleration, is it possible to reverse its direction...

For a moving particle which has a constant acceleration, is it possible to reverse its direction of motion? Explain the reason of your answer briefly.

Science   Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Yes for a particle moving with uniform acceleration it is possible to reverse it's direction of motion. Take example of vertical motion, if a ball is thrown upwards it's velocity decreases but the acceleration is uniform. At the highest point velocity becomes zero and ball starts to fall back, the direction of motion changes but the acceleration remains constant.

Acceleration doesn't guide the motion or the direction of motion doesn't depend on acceleration.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A particle moving along the x axis in simple harmonic motion starts from its equilibrium position,...
A particle moving along the x axis in simple harmonic motion starts from its equilibrium position, the maximum value, at t = 0, moving to the right. The amplitude of the motion is 2.00 cm and the frequency is 1.50 Hz. (a) Find an expression for the position of the particle as a function of time. Determine (b) the maximum speed of the particle and (c) the earliest time (t > 0) at which the particle has this speed. Find...
The acceleration of a particle moving only on a horizontal xy plane is given by a→=3ti^+4tj^,...
The acceleration of a particle moving only on a horizontal xy plane is given by a→=3ti^+4tj^, where a→ is in meters per second-squared and t is in seconds. At t = 0, the position vector r→=(19.0m)i^+(44.0m)j^ locates the particle, which then has the velocity vector v→=(5.40m/s)i^+(1.70m/s)j^. At t = 4.10 s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis?
The position of a particle moving with constant acceleration is given by x(t) = 2t2 +...
The position of a particle moving with constant acceleration is given by x(t) = 2t2 + 8t + 4 where x is in meters and t is in seconds. (a) Calculate the average velocity of this particle between t = 6 seconds and t = 9 seconds.   (b) At what time during this interval is the average velocity equal to the instantaneous velocity?   
) Will the position, velocity, and/or the acceleration vector(s) always be in the direction of the...
) Will the position, velocity, and/or the acceleration vector(s) always be in the direction of the E field at each point for a moving positively charged particle? Explain. f) How is the answer to e) different (if at all) for a moving negative charge?
Which one of the following statements is not possible? An object has zero velocity and non-zero...
Which one of the following statements is not possible? An object has zero velocity and non-zero acceleration An object travels with a northward velocity and a northward acceleration An object travels with a constant velocity and a constant non-zero acceleration An object travels with a changing velocity and a constant acceleration              ____________ In a displacement vs. time graph, a sloped (non-horizontal) line indicates: The object is moving with constant, non-zero, acceleration The total displacement of the object is zero...
The position of a particle moving with constant acceleration is given by x(t) = 4t2 +...
The position of a particle moving with constant acceleration is given by x(t) = 4t2 + 3t + 4 where x is in meters and t is in seconds. (a) Calculate the average velocity of this particle between t = 2 seconds and t = 7 seconds. (b) At what time during this interval is the average velocity equal to the instantaneous velocity? (c) How does this time compare to the average time for this interval? a. It is larger....
an object which is moving has a net force acting on it in the direction of...
an object which is moving has a net force acting on it in the direction of motion. a-definitely, b-maybe, c-no way
A particle is moving along a straight line and has acceleration given by a(t) = 20t^3+12t^2}....
A particle is moving along a straight line and has acceleration given by a(t) = 20t^3+12t^2}. Its initial velocity is v( 0 ) = 4 m / s and its initial displacement is s( 0 ) = 5 m. Find the position of the particle at t = 1 seconds.
A point charge q is moving in uniform electric field (E0 in the z-direction) and uniform...
A point charge q is moving in uniform electric field (E0 in the z-direction) and uniform magnetic field (B0 field in the x-direction). (i) What is the force acting on the charge particle? Find equations of motion for the charge particle. (ii) Assume that initially the charge is placed the origin and has initial velocity (E0/2B0) in the y-direction. Determine position and velocity of the charge particle as a function of time. (iii) Find the trajectory of the particle and...
The acceleration of a particle moving only on a horizontal xy plane is given by ModifyingAbove...
The acceleration of a particle moving only on a horizontal xy plane is given by ModifyingAbove a With right-arrow equals 4t ModifyingAbove i With caret plus 5t ModifyingAbove j With caret, where ModifyingAbove a With right-arrow is in meters per second-squared and t is in seconds. At t = 0, the position vector ModifyingAbove r With right-arrow equals left-parenthesis 24.0mright-parenthesis ModifyingAbove i With caret plus left-parenthesis 49.0mright-parenthesis ModifyingAbove j With caret locates the particle, which then has the velocity vector...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT