A solid block is attached to a spring scale. The reading on the scale when the block is completely immersed in water is 25.1 N , and the reading when it is completely immersed in alcohol of density 806 kg/m3 is 25.7 N .
What is the block's volume?
What is the block's density?
density of air da = 1.225 kg/m^3
density of water dw =1000kg/m^3
denisty of alcohol dl = 806 kg/m^3
weight=mg
mass =denisty /volume
Weight of block in water is Fnet = 25.1 N
Fnet = weight of block in air - weight of displaced water
Fnet = dbVg - dwVg
25.1 = dbV*9.8 - 1000V*9.8 ... (1)
Weight of block in alchohol is Fnet = 25.7 N
Fnet = weight of block in air - weight of displaced alchohol
Fnet = dbVg - dlVg
25.7 = dbV*9.8 - 806V*9.8 ... (2)
By sloving (1) and (2) we get
volume of block V = 0.000315 m^3
density of block db= 9115.66 kg/m^3
Get Answers For Free
Most questions answered within 1 hours.