Use the approximation that v ≈ pf/m for each time step. You throw a metal block of mass 0.26 kg into the air, and it leaves your hand at time t = 0 at location 0, 2, 0 m with velocity 3.5, 5.5, 0 m/s. At this low velocity air resistance is negligible. Using the iterative method shown in Section 2.4 with a time step of 0.05 s, calculate step by step the position and velocity of the block at t = 0.05 s, t = 0.10 s, and t = 0.15 s. (Express your answers in vector form.)
r(t = 0.05 s) = m
v(t = 0.05 s) = m/s
r(t = 0.10 s) = m
v(t = 0.10 s) = m/s
r(t = 0.15 s) = m
v(t = 0.15 s) = m/s
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