Question

A proton accelerates from rest in a uniform electric field of
630 N/C. At one later moment, its speed is 1.10 Mm/s
(nonrelativistic because *v* is much less than the speed of
light).

(a) Find the acceleration of the proton.

m/s^{2}

(b) Over what time interval does the proton reach this speed?

s

(c) How far does it move in this time interval?

m

(d) What is its kinetic energy at the end of this interval?

J

Answer #1

11. A proton accelerates from rest in a uniform electric field
of 650 N/C. At one later moment, its speed is 1.10 Mm/s
(nonrelativistic because v is much less than the speed of
light).
(a) Find the acceleration of the proton.
m/s2
(b) Over what time interval does the proton reach this speed?
s
(c) How far does it move in this time interval?
m
(d) What is its kinetic energy at the end of this interval?
J

A proton accelerates from rest in a uniform electric field of
630 N/C. At some later time, its speed is 1.34 106 m/s.
(a) Find the magnitude of the acceleration of the proton.
6.04e10 Correct: Your answer is correct. m/s2
(b) How long does it take the proton to reach this speed? Use
the acceleration you calculated in part (a) of this problem to find
the time required for the proton to reach the specified speed.
µs
(c) How far...

A proton accelerates from rest in a uniform electric field of
668 N/C. At some later time, its speed is 1.12 106 m/s. (a) Find
the magnitude of the acceleration of the proton. m/s2 (b) How long
does it take the proton to reach this speed? µs (c) How far has it
moved in that interval? m (d) What is its kinetic energy at the
later time? J

A proton accelerates from rest in a uniform electric field of
654 N/C. At some later time, its speed is 1.22 106
m/s.
(a) Find the magnitude of the acceleration of the proton.
m/s2
(b) How long does it take the proton to reach this speed?
µs
(c) How far has it moved in that interval?
m
(d) What is its kinetic energy at the later time?
J

A proton accelerates from rest in a uniform electric field of
602 N/C. At some later time, its speed is 1.14 106 m/s.
(a) Find the magnitude of the acceleration of the proton.
57700000000 Correct: Your answer is correct. m/s2
(b) How long does it take the proton to reach this speed?
0.0000198 Incorrect: Your answer is incorrect. . µs
(c) How far has it moved in that interval?
? m
(d) What is its kinetic energy at the later...

A proton accelerates from rest in a uniform electric field of
674 N/C. At some later time, its speed is
1.34 106 m/s.
(a) Find the magnitude of the acceleration of the proton.
(b) How long does it take the proton to reach this speed?
Use the acceleration you calculated in part (a) of this problem to
find the time required for the proton to reach the specified speed.
µs
(c) How far has it moved in that interval?
m
(d)...

A proton accelerates from rest in a uniform electric field of
580 N/C. At some later time, its speed is found to be 3.6 ✕ 106
m/s.
(a)
Calculate the magnitude of the acceleration of the proton (in
m/s2).
m/s2
(b)
How long (in s) does it take the proton to reach the given
speed?
s
3.
[–/1 Points]
DETAILS

A) A proton accelerates from rest in a uniform electric field of
673 N/C. At some time later, its speed is 2.00 × 106 m/s. What is
the magnitude of its acceleration? The mass of a proton is 1.6726 ×
10−27 kg and the fundamental charge is 1.602 × 10−19 C . Answer in
units of m/s 2 .
B) How long does it take the proton to reach this speed?
C) How far has it moved in this time...

A proton is initially at rest. After some time, a uniform
electric field is turned on and the proton accelerates. The
magnitude of the electric field is 1.27 105 N/C.
(a) What is the speed of the proton after it has traveled 3.00
cm? m/s
(b) What is the speed of the proton after it has traveled 30.0
cm? m/s

An electric vehicle starts from rest and accelerates at a rate
of 2.1 m/s2 in a straight line until it reaches a speed
of 19 m/s. The vehicle then slows at a constant rate of 1.3
m/s2 until it stops. (a) How much time
elapses from start to stop? (b) How far does the
vehicle move from start to stop

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