An object is launched at an angle of 60 degrees above the horizontal from the roof of a building 50 m above the horizontal ground. Find its horizontal angle if the object is launched with an initial speed of 111 m/s. Is this correct and if not can you show me what to do please?
Theta=60
V (initial)=111 m/s
LnY:
A=-9.81
V (initial)=111 * sin (60)= 96.13 m/s
V (Final)= V(initial) + a*t
0=96.13+ (-9.81*t)
T= 9.8 seconds
LnX:
D=V(initial)*t+(1/2 *0*9.8^2)
D=543.9 meters
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