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An object is launched at an angle of 60 degrees above the horizontal from the roof...

An object is launched at an angle of 60 degrees above the horizontal from the roof of a building 50 m above the horizontal ground. Find its horizontal angle if the object is launched with an initial speed of 111 m/s. Is this correct and if not can you show me what to do please?

Theta=60

V (initial)=111 m/s

LnY:

A=-9.81

V (initial)=111 * sin (60)= 96.13 m/s

V (Final)= V(initial) + a*t

0=96.13+ (-9.81*t)

T= 9.8 seconds

LnX:

D=V(initial)*t+(1/2 *0*9.8^2)

D=543.9 meters

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