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An oscillation can be described by the equation: x = 10.6(cm) * cos(87.6(hz) * t(sec) +...

An oscillation can be described by the equation: x = 10.6(cm) * cos(87.6(hz) * t(sec) + 75.9). Based on this equation, what is the period of the oscillation in seconds?

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Answer #1

Solution.) From the equation-

=87.6 hz

Spring constant k=75.9 N/m

we know that,

2=k/m

So, m=k/2

m=75.9/(87.6)2

m=0.00989 kg

Now, Period of oscillation

= T=2(m/k)

T=2××(0.00989/75.9)

T=0.07168 sec.

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