please show all steps.
2.5 kg of nitrogen gas with an initial temperature of 300 K and pressure of 100 kPa is compressed to a higher pressure. The internal energy change during this process is 70 kJ/kg. Determine the final temperature of the nitrogen. Please perform at least two iterations with average specific heats.
Solution:
Using the information given,
U = nCvT = nCV[Tf - Ti]
n = m/M = 2.5*103/28.014 g/mol = 89.24 mols
Cv = 5/2R [diatomic gas] and R = 8.314,
Cv = 20.785
Ti = 300K
Substitute the values,
Tf = Ti + U/nCv
= 300 + 70*103/89.24*20.785
= 300 + 37.74
= 337.74 K.
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