Three point charges are arranged along the x-axis. Charge q1 = +3.75 µC is at the origin, and charge q2 = -5.25 µC is at x = 0.300 m. Charge q3 = -9.00 µC. Where is q3 located if the net force on q1 is 6.00 N in the −x-direction?
equate the resultant force on q1 = 6 N.
the charge q1 is at centre.let me explain..
the charge q1 is positive and the charge q2 ia negative and at the right side of q1 ao the force between the q1 and q2 will be in positive x direction due to attractive forcebetween the different charge particles so the other charge q3 should be left of q1 as the q3 is negative and so the attractive force should be more than the q2 charge.
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