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How much energy is released when a neutron(1.67493 10-27 kg) decays into a proton (1.67262 10-27...

How much energy is released when a neutron(1.67493 10-27 kg) decays into a proton (1.67262 10-27 kg), an electron(9.10938 10-31 kg), and a neutrino of negligible mass?

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Answer #1

Energy released in above reaction will be given by:

Q = dm*c^2

Q = (mn + - mp - me)*c^2

mp = mass of proton & mn = mass of neutron & me = mass of electron

mass of neutrino is negligible​

c = speed of light = 3*10^8 m/sec

Using these given values:

Q = (1.67493*10^-27 - 1.67262*10^-27 - 9.10938*10^-31)*(3*10^8)^2

Q = 1.25916*10^-13 J (if you need your answer in J)

Q = 1.25916*10^-13/(1.6*10^-19) eV = 786975 eV

Q = 0.786975 MeV (if you need your answer in eV)

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