Question

The upper half of the ring with radius R is +Q, the lower half with -Q. The q charged particle has the velocity V0 , 10R from the center. What speed does it get when the particle reaches 3R?

Q = 5.0 C R = 6.0 cm q = 2.0 C m= 2.0x10^-6 kg V0 = 5.0x10^4 m/s

Answer 1

Given :

One half of ring is positively charged +Q

other half of ring is negatively charged -Q.

As the net charge is zero, and any point on the axis is equidistant from both the segment, so net potential at any point on the axis is zero.

So, whether the charge particle q is at 10 R distance or 3R distance from the center, the potential difference between the two points is zero, so there is no work done, therefore, there will be no change in kinetic energy of the particle.

Therefore, The speed at 3R distance is same as speed at 10R distance i.e; .[answer]