Question

An object starting from rest experiences constant acceleration. If it travels 2.2 m in the first 0.45 seconds, how far will it move in the next 0.45 seconds?

Answer 1

Using Equation

S = U*t + 0.5*a*t^2

Using given values

S = 2.2 m, U = initial Velocity = 0 m/sec

time taken = t = 0.45 sec, So

2.2 = 0*0.45 + 0.5*a*0.45^2

a = 2.2/(0.5*0.45^2)

a = 21.73 m/sec^2,

Now it's speed after first 0.45 sec will be

V = U + a*t

V = 0 + 21.73*0.45

V = 9.78 m/sec

Now take this as intial velocity and calculate distance traveled in next 0.45 sec

S1 = 9.78*0.45 + 0.5*21.73*0.45^2

S1 = 6.6 m

Method 2

Calculate total distance traveled by object in 0.90 sec

S2 = 0*0.90 + 0.5*21.73*0.90^2

S2 = 8.8 m

Now subtractc distance traveled in first 0.45 sec

S1 = S2 - S = 8.8 - 2.2

S1 = 6.6 m

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