Question

Calculating speed and constant velocity.

A rock is released at t = 0.00 s from the top of a tall building. Its speed at t = 1.18 s is

A. 12.0 m/s

B. 11.6 m/s

C. 1.12 m/s

D. 11.0 m/s

Which of the following statements concerning a constant velocity motion is incorrect?

A. The acceleration is a non-zero constant.

B. The speed is constant.

C. The direction of motion does not change.

Which of the following statements concerning a constant velocity motion is correct?

A. The motion has a constant zero acceleration

B. The acceleration changes with time

C. Equal distances are traveled in equal intervals of time

D. The distance traveled does not change with time

Answer 1

initial velocity u= 0

acceleration a = g =9.8 m/s²

final velocity after time t= 1.98 can be given by

v=u + at

=0+9.8*1.18

=11.56 m/s

Contant velocity means direction and magnitude of velocity will not change with time which is possibe only when acceleration is zero.

correct answer (A)

Contant velocity means direction and magnitude of velocity will not change with time which is possibe only when acceleration is zero. with constant velocity v distance travelled in equal time t will be equal= v*t

correct answer (A), (C)