Question

An object object travels 31 meters in the +x direction for 3.2 seconds, and then immediately travels some distance in the -x direction. After a total time of 7.7 seconds, the object's average velocity is 0 m/s. What is the average velocity for the second part of the trip (traveling in the -x direction) in m/s? If in the negative x direction, indicate so with a negative sign.

PLEASE SHOW WORK!!!!

Answer 1

for the first trip

displacement x_1 = 31 meters

time taken t_1 = 3.2 seconds

for the second trip

displacement = x_2

time taken t_2 = ?

for the entire trip

average velocity v = 0

average velocity v = total displacement/total time interval

0 = (x-1+x_2)/(t_1+t_2)

x_2 = -x_1 = -31 meters

total time taken t = t_1 + t_2 = 7.7 seconds

t_2 = 7.7 - 3.2 = 4.5 seconds

averge velocity for second part

v2 = x2/t2 = -31/4.5 = -6.9 m/s <<<<<----------answer