An archer on the roof of a tower shoots an arrow at a bird in flight. The arrow travels at 255 m/s. The bird is directly across from the archer at a distance of 90.0 m. The archer misses. If the tower is 200 m tall and if we assume the cow is at ground level, will his stray arrow hit the cow? (The cow is 145 m away from the tower.)
consider the motion along the Y-direction
Voy = initial velocity = 0 m/s (since the arrow was launched horizontally)
a = acceleration = - 9.8
Y = vertical displacement = height of the tower= - 200 m
t = time of travel = ?
using the equation
Y = Voy t + (0.5) a t2
- 200 = 0 t + (0.5) (- 9.8) t2
t = 6.4 sec
consider the motion along the X-direction
Vox = initial velocity = 255 m/s
X = horizontal displacement = ?
using the equation
X = Vox t
X = 255 x 6.4
X = 1632 m
hence the arrow hits the cow
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