Question

A sailboat runs before the wind with a constant speed of 4.0 m/s in a direction 32 ∘ north of west.

How far west has the sailboat traveled in 29 min ?

How far north has the sailboat traveled in 29 min ?   

Answer 1

Given that Speed of sailboat is

V = 4.0 m/sec in direction 32 deg N of W (In 2nd quadrant, x -ve and y +ve)

Vx = x-component of velocity = -4.0*cos 32 deg = -3.39 m/sec

Vy = y-component of velocity = 4.0*sin 32 deg = 2.12 m/sec

Now since sailboat is moving with constant speed, So

distance traveled in west direction will be:

d1 = |Vx|*t

t = 29 min = 29*60 sec

d1 = 3.39*29*60 = 5898.6 m = 5.9*10^3 m

distance traveled in north direction will be:

d2 = |Vy|*t

t = 29 min = 29*60 sec

d2 = 2.12*29*60 = 3688.8 m = 3.7*10^3 m

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