Question

A golfer gives a ball a maximum initial speed of 51.4 m/s.

What is the longest possible hole-in-one for this golfer? Neglect any distance the ball might roll on the green and assume that the tee and the green are at the same level. What is the minimum speed of the ball during this hole-in-one shot?

Answer 1

Given,

Initial speed, v = 51.4 m/s

For maximum range, angle should be 45°

Horizontal component, Vx = 51.4 x cos45° = 36.35 m/s

Vertical component, Vy = 51.4 x sin45° = 36.35 m/s

Using 2nd equation of motion,

d = ut + 0.5 a t²

0 = 36.35 t + 0.5 x (-9.8) t²

t = 7.42 seconds

Dx = Vx * t = 36.35 x 7.42 = 269.62 m

B) Minimum speed happens when the vertical velocity is 0 at the top of the arc of the ball. So, minimum speed is 36.35 m/s

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