Question

Sam takes off from rest down a 50m high 10 degree slope on his jet-powered skis. The jets on his skis still have a thrust of 200 N and Sam's mass is still 75kg.

If sam's speed is 40m/s at the bottom of the hill, what is the coefficient of kinetic friction between his skis and the snow?

Answer #1

here,

mass of Sam , m = 75 kg

height , h = 50 m

theta = 10 degree

thrust due to jets , Ft = 200 N

normal force , N = m * g * cos(theta)

the length of slope ,s = h/sin(theta)

let the coefficient of kinetic friction be uk

using work energy theorm

total work done = kinetic energy gained

Wt + Wg + Wff = KE

Ft * s + m * g * H - uk * N * s = 0.5 * m * v^2

Ft * (h /sin(theta)) + m * g * H - uk * N * (h/sin(theta)) = 0.5 * m * v^2

200 * ( 50/sin(10)) + 75 * 9.81 * 50 - uk * 75 * 9.81 * cos(10) * ( 50/sin(10)) = 0.5 * 75 * 40^2

solving for uk

uk = 0.16

the coefficient of kientic friction is 0.16

Jason takes off from rest down a 50 m tall, 10.0° degree slope
on his jet-powered skis. The skis have a thrust force of 280 N,
directed so that the force pushes Jason forward along the slope.
The combined mass of skis and Jason is 50.0 kg. Jason’s speed at
the bottom of the hill is 40.0 m/s. What is the magnitude of the
frictional force that must be acting on the skis?

Jason takes off across level water on his jet-powered skis. The
combined mass of Jason and his skis is 75kg (the mass of the the
fuel is negligible). The skis produce a forward thrust of 200 N and
have a coefficient of kinetic friction with water of 0.10.
Unfortunately, the skis run out of fuel after only 41 seconds. How
far from his starting point has Jason traveled when he finally
coasts to a stop?
Correct answer: 3900m Show with...

Jason takes off across level water on his jet-powered skis. The
combined mass of Jason and his skis is 75 kg (the mass of the fuel
is negligible). The skis produce a forward thrust of 200 N and have
a coefficient of kinetic friction with water of 0.10.
Unfortunately, the skis run out of fuel after only 90 s. What is
Jason's top speed?
Answer options:
150 m/s
240 m/s
24 m/s
90 m/s

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Edit: This is the question...

ch 6
1:
It is generally a good idea to gain an understanding of the
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energy of each one.
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.
×10
J
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.
J
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5:
The graph shows the ?-directed force
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