A satellite of mass 5570 kg orbits the Earth and has a period of 6600 s .
determine the radius of its circular orbit.
Express your answer using three significant figures and include the appropriate units.
|
||||||||||
r = Determine the magnitude of the Earth's gravitational force on the satellite. Express your answer using three significant figures and include the appropriate units.
|
1.
Using force balance on satellite
Fg = Fc
G*M*m/R^2 = m*V^2/R
V = sqrt (G*M/R)
Time period is given by
T = 2*pi/w = 2*pi*R/V
T = 2*pi*sqrt (R^3/GM)
R^3 = G*M*T^2/(4*pi^2)
R = [G*M*T^2/(4*pi^2)]^(1/3)
Using given values
M = Mass of earth = 5.98*10^24 kg
T = time period = 6600 sec
G = 6.67*10^-11
So,
R = [6.67*10^-11*5.98*10^24*6600^2/(4*pi^2)]^(1/3)
R = 7.61*10^6 m
Part B.
Now gravitation force on satellite will be
Fg = G*M*m/R^2
m = mass of satellite = 5570 kg
So,
Fg = 6.67*10^-11*5.98*10^24*5570/(7.61*10^6)^2
Fg = 38363.0 N
Fg = 3.84*10^4 N
Part C.
Altitude of satellite = Radius of orbit - Radius of earth
Altitude of satellite = R - Re
Altitude of satellite = 7.61*10^6 - 6.37*10^6
Altitude of satellite = 1.24*10^6 m
Please Upvote.
Comment below if you have any doubt.
Get Answers For Free
Most questions answered within 1 hours.