1.velocity along northern direction is, V is the actual velocity and theta (@) is the angle between the actual velocity and positive y axis.
North component velocity = (cos 41.5 x 835) = (1.4 x 625.178) =
625.378 km/h
West component velocity = (sin 41.5 x 835) = 553.2877 km/h
after 4 hour distance covered by north coponent =625.378*4=2501.512
after 4 hour distance covered by south coponent=553.2877*4=2213.1508
so Dnorth-Dsouth= 2501.512-2213.1508288.36km
2.by equation we have
y= vsin(@)t+ 0.5 at^2
for hitting the ground y=0
which gives t= -2vsin(@)/g
here g= -9.8m/s (g is acting downbard)
t=2.159 sec
3. Hmax= vsin(@)^2/2g
=(36.5sin(44.1))^2/2(9.8)
=32.918m
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