Question

The number of moles in a sample of diatomic gas molecules is such that nR = 300 J/K. The initial volume of this sample of gas is Va, and its initial temperature is Ta =250 K. The volume of this sample of gas is doubled (Vb =2 Va) in a constant pressure (isobaric) process and its temperature increases to Tb. What is the change in entropy DS of this gas sample as a result of the isobaric expansion to a volume 2V?

(A) Delta S = 728 J/K increase

(B) Delta S = 728 J/K decrease

(C) Delta S = 970 J/K increase

(D) Delta S = 970 J/K decrease

(E) Delta S = 0 (entropy does not change during an isobaric
expansion)

Answer #1

When n moles of a monotonic gas undergo an adiabatic process,
the temperature, pressure, and volume change from (Ta, pa, Va) to
(Tb, pb, Vb). If pb<pa, which statement is false?
(A) Vb >Va
(B) Tb <Ta
(C) The change in internal energy is DU=Ub – Ua = 3/2 (pbVb –
paVa).
(D) The temperature Tb is given by Tb = Ta (Va/Vb)g.
(E) The change in entropy is zero.

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