Question

An electric generator is designed to produce a maximum emf of
220 V while rotating with an angular speed of 3600 rpm. Each coil
of the generator has an area of 0.027 m^{2}.

**a.)** If the magnetic field used in the generator
has a magnitude of 0.050 T, how many turns of wire are
needed?

**b.)** During the rotation of the coils, the magnetic
flux through the coils will alternately be increasing and
decreasing. *(Why?)*

While the flux is **increasing**, the induced current
in the coils will make a B field which tries
to ---Select--- oppose reinforce none of the above not
enough info the external B field.

While the flux is **decreasing**, the induced current
in the coils will make a B field which tries
to ---Select--- oppose reinforce none of the above not
enough info the external B field.

This generator will produce what kind of
current? ---Select--- DC (direct current) AC
(alternating current) none of the above not enough info

**c.)** The generator is connected to a resistor of
R=250 Ω, and the magnitude of current passing through it and its
rate of power dissipation are measured over time. What are the
extremes of the measured values?

Also, give the angle between the normal vector to the loops and the
magnetic field when these extremes occur. *(If ambiguous, state
the smallest angle.)*

I_{max} = A

P_{max} = W

*θ* = degrees

I_{min} = A

P_{min} = W

*θ* = degrees

Answer #1

emf = -d(flux)/dt = B*A*sin(theta)* d(theta)/dt

= B*A*sin(theta)* omega

Here n is the number of turns

emf = n*B*A*sin(theta)*omega

Therefore, max. emf = n*B*A*omega

Hence n = 220 /(0.05*0.027*3600*2*pi/60) = 432.27

B) flux = B*A*cos(theta) [ here theta is the angle between B and
A]

-1 <= sin(theta) <=1

Therefore, the magnetic flux will be increasing and decreasing over
time

the induced current in the coils will make a field B which tries to
oppose when the flux is increasing,

Also, the induced current in the coils make a field B which tries
to reinforce while the flux is decreasing,

The generator will produce Alternative current

C) Imax = Emax/R = 220/250 = 0.88

Pmax = Imax^2 * R = 193.6

Here angle = 0

Imin = Emin/R = 0/250 = 0

Pmax = 0

So angle will be 90 degrees.

A generator is designed to produce a maximum emf of 150 V while
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generator has an area of 1.9×10−2 m2.If the magnetic field used in
the generator has a magnitude of 4.9×10−2 T , how many turns of
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