Question

Graph a vs. t and v vs. t for the following situation(all motion relative to the X direction): an object has a constant velocity of -1.0 m/s for 2 seconds, then accelerates at 2.0 m/s^2 for 2 seconds, travels with a constant velocity of 3.0 m/s for 1.0 second then accelrates in the negative direction with an acceleration of 2.0 m/s^2 for 3.0 seconds.

Answer #1

Graph (a vs t) and (v vs t) for the following situation(all motion in the x direction). He has a constant velocity of -1.0m/s for 2 seconds, then accelerates at 2.0 m/s*s fr 2 seconds,travels with constant velocity of 3.0 m/s for 1 second thenaccelerates in the negative direction with an acceleration of 2.0m/s*s for 3 seconds.

Also, what is the displacement to the origin after the
lastdescribed motion?

displacement in 2 sec=-2m

velocity after 2 sec=-1m/sec

displacement during accelerated period=-1*2+1/2*2*4=-2+4=2m

velocity after 4sec=-1+2*2=3m/sec

displacement in the third phase=3*1=3m

displacement in the last phase=-3*3-1/2*2*9=-18m

hence total displacement=-2+2+3-18=-15m

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