Question

An object with a density of 681.0 kg/m3 and a mass of 1831.0 kg is thrown...

An object with a density of 681.0 kg/m3 and a mass of 1831.0 kg is thrown into the ocean. Find the volume that sticks out of the water. (use ρseawater = 1024 kg/m3)

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Answer #1

Gravitational acceleration = g = 9.81 m/s2

Density of seawater = w = 1024 kg/m3

Mass of the object = M = 1831 kg

Density of the object = = 681 kg/m3

Volume of the object = V

M = V

1831 = (681)V

V = 2.689 m3

Volume of the object submerged under seawater = Vs

Buoyancy force on the object = Fb = wVsg

The object floats in seawater therefore the buoyancy force on the object is equal to the weight of the object.

Mg = Fb

Mg = wVsg

M = wVs

1831 = (1024)Vs

Vs = 1.788 m3

Volume of the object that sticks out of the water = V0

V = Vs + V0

2.689 = 1.788 + V0

V0 = 0.901 m3

Volume of the object that sticks out of the water = 0.901 m3

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