A simple pendulum has a period of 0.777 s on Earth. What is its period on a planet on which the acceleration of gravity is 2.89 m/s2?
Gravitational acceleration on Earth = g1 = 9.81 m/s2
Length of the pendulum = L
Time period of the pendulum on Earth = T1 = 0.777 sec
Time period of a simple pendulum is given by,
Squaring both sides,
L = 0.15 m
Gravitational acceleration on the new planet = g2 = 2.89 m/s2
Time period of the pendulum on this new planet = T2
T2 = 1.43 sec
Time period of the pendulum on this new planet = 1.43 sec
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