Question

(a) What is the energy in joules of an x-ray photon with wavelength 2.08 ✕ 10⁻¹⁰ m?
J

(b) Convert the energy to electron volts.
keV

(c) If more penetrating x-rays are desired, should the wavelength be increased or decreased?

increaseddecreased     

(d) Should the frequency be increased or decreased?

increaseddecreased

Answer 1

a)
energy of photon=h*c/wavelength

where h=planck's constant

c=speed of light

so putting the values, we get energy=9.556*10^(-16) J

b) 1 eV=1.6*10^(-19) J

so 9.556*10^(-16) J=(9.556*10^(-16))/(1.6*10^(-19)) eV=5973 eV

c)more penetrating x rays means more energy.

to achieve that, we need lesser wavelength as energy varies inveresely with wavelength.

d) as energy=h*frequency

energy varies linearly with frequency

so for more energy, frequency should be increased.