At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of the mirror's radius of curvature is 0.542 m.
(a) Locate the image of a patient 10.2 m from the mirror. (Use
the correct sign conventions.)
Apply the mirror equation using the correct focal length and object
distance to find the image distance. cm (from the mirror)
(b) Determine the magnification of the image.
(a)Here, the mirror is convex, so the radius of curvature would be in negative
R = -0.542 m
= 10.2 m
The Image distance is
...................................
Substituting the values
=-0.263 m
= -26.3 cm
Hence the image is virtual and located 26.3 cm behind the mirror.
(b) The magnification of the image
M= 0.0257
As the magnification is greater than zero so the image is upright.
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