Problem 31.56----Unpolarized light of intensity I0 is incident on three polarizing filters. The axis of the first is vertical, that of the second is 45.0 ∘ from vertical, and that of the third is horizontal. What light intensity emerges from the third filter?
after passing from the first polarizer Unpolarized light of intensity become 1/2 always !! yeah always
fraction after passing from first = 1/2
frcation after passing throught 2nd is given by malus law I= I_previous* cos2φ
where φ is the angle between 1st and 2nd polarizer = 45
so fraction after passing through 2nd = 1/2* cos( 45) *cos45 = 1/ 4
the angle between 2nd and3rd filter = 90-45 = 45
so fraction after passing through 3rd = 1/4* cos(45)*cos45 = 1/ 8
light intensity emerges from the third filter = Io/8 =0.125 *Io
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