When you skid to a stop on your bike, you can significantly heat the small patch of tire that rubs against the road surface. Suppose a person skids to a stop by hitting the brake on his back tire, which supports half the 90 kg combined mass of the bike and rider, leaving a skid mark that is 36 cm long. Assume a coefficient of kinetic friction of 0.80.
How much thermal energy is deposited in the tire and the road surface?
Gravitational acceleration = g = 9.81 m/s2
Mass of the bike and rider = m = 90 kg
Normal force on the back tire = N
The back tire supports half the weight of the bike and rider.
N = mg/2
Coefficient of kinetic friction = = 0.8
Friction force on the tire = f
f = N
f = (mg/2)
f = mg/2
Length of the skid mark = L = 36 cm = 0.36 m
Thermal energy deposited in the tire and the road surface = E
The thermal energy deposited in the tire and the road surface is equal to the work done by friction.
E = fL
E = (mg/2)L
E = mgL/2
E = (0.8)(90)(9.81)(0.36)/2
E = 127.14 J
Thermal energy deposited in the tire and the road surface = 127.14 J
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