Question

IA weight of mass 6.89 kg is suspended by a string of length
0.849 m, and set into motion along circular horizontal path (see
figure). The angle \theta*?* of the string with respect to
vertical is 5.61^o?*o*??. What is the period of the circular
motion? I can not uplaod the image!

Also I got 11 for this problem but apparently that is wrong: A
mass, *m*?1??=24.9 kg mass is placed on a frictionless ramp
which is inclined 43.5^\circ???? above horizontal. It is connected
to a second mass, *m*?2??, by a strong rope which runs over
a pulley at the apex of the ramp, so that the second mass is
suspended in the air next to the ramp, as shown in the figure.
Calculate the value of *m*?2?? necessary so that the first
mass accelerates *up* the incline at rate of 1.66
m/s^2???.

I did 24.9*sin(43.5)-1.66/[1.66+9.8]

Answer #1

in vertical,

T cos5.61 = m g = 6.89 x 9.8

T = (6.89 x 9.8)/cos5.61

in horizontal,

T sin5.61 = m v^2/ r

(6.89 x 9.8 / cos5.61) = 6.89 v^2 / (0.849 x sin5.61)

v = 0.904 m/s

anr r = 0.849 sin5.61 = 0.083 m

T = 2 pi r / v = 0.577 sec ......Ans

------------------------------------

on m1:

T - m1 g sin43.5 = m1 a

on m2:

m2 g - T = m2 a

9.8 m2 - (24.9 x 9.8 x sin43.5) = (24.9 x 1.66) + 1.66 m2

m2 = ((24.9 x 9.8 x sin43.5) + (24.9 x 1.66))/(1.66 + 9.8)

m2 = 18.3 kg

A bob of mass m = 0.300 kg is suspended from a fixed
point with a massless string of length L = 21.0 cm . You
will investigate the motion in which the string traces a conical
surface with half-angle θ = 22.0
What tangential speed v must the bob have so that it
moves in a horizontal circle with the string making an angle 22.0 ∘
with the vertical?
Express your answer numerically in meters per second.

A mass of 4.83 kg is suspended from a 1.91 m long string. It
revolves in a horizontal circle. If the string makes an angle of
56.9 degrees with the vertical, then what is the net force acting
on the mass?

A conical pendulum consists of a mass m suspended by a
massless string of length l as shown. The mass rotates in a
horizontal circle at fixed angular velocity ω so that the string
makes a constant angle β with the vertical. Show that the angular
velocity of rotation is given by ω = √g/l cos β.

1. An object of mass 1.2 kg is attached to a string of 0.83 m.
When this object is rotated around a horizontal circle, it
completes 15 revolutions in 9.6 seconds.
a. What is the period (T) of this motion?
b. What is the tangential velocity of the object?
c. What is the tension on the string? Hint: The tension on the
string is the centripetal force that causes the circular
motion.

A small ball of clay of mass m hangs from a string of length L
(the other end of which is fixed). A seond ball of clay of mass m/3
is to be launched horizontally out of a spring with spring constant
k. Once launched, the second ball will collide with and stick to
the hanging ball, and they'll follow a circular path around the
fixed end of the string.
A) Determine an expression for the distance (change in x)...

A pendulum consists of a 5.2 kg ball suspended by a 1.3 m length
of string with negligible mass and is initially at rest. A 4.4 g
bullet travelling at 680 m/s is fired horizontally into the ball
and is lodged there. The ball and bullet rise together to a maximum
height of h. How long does it take from the moment of impact for
the ball to first reach its maximum height?

Two objects with masses of m1 = 3.90 kg and
m2 = 5.70 kg are connected by a light string
that passes over a frictionless pulley, as in the figure below.
A string passes over a pulley which is suspended from a
horizontal surface. A circular object of mass
m1 and a rectangular object of
m2 are, respectively, attached to the left and
right ends of the string.
(a) Determine the tension in the string. (Enter the magnitude
only. Due...

A hanging weight, with a mass of m1 = 0.370
kg, is attached by a string to a block with mass
m2 = 0.850 kg as shown in the figure below. The
string goes over a pulley with a mass of M = 0.350 kg. The
pulley can be modeled as a hollow cylinder with an inner radius of
R1 = 0.0200 m, and an outer radius of
R2 = 0.0300 m; the mass of the spokes is
negligible. As...

1. For a stationary ball of mass m = 0.200 kg hanging from a
massless string, draw arrows (click on the “Shapes” tab) showing
the forces acting on the ball (lengths can be arbitrary, but get
the relative lengths of each force roughly correct). For this case
of zero acceleration, use Newton’s 2nd law to find the
magnitude of the tension force in the string, in units of Newtons.
Since we will be considering motion in the horizontal xy plane,...

An object with a mass of m = 5.5 kg is attached to the free end
of a light string wrapped around a reel of radius R = 0.260 m and
mass of M = 3.00 kg. The reel is a solid disk, free to rotate in a
vertical plane about the horizontal axis passing through its center
as shown in the figure below. The suspended object is released from
rest 6.40 m above the floor. (a) Determine the tension...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 29 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 3 hours ago

asked 3 hours ago

asked 3 hours ago