Question

The electric potential due to a point charge is given by V = k q /...

The electric potential due to a point charge is given by V = k q / r where q is the charge, r is the distance from q, and k =8.99×109Nm2⁄C2.

A) Show, in detail, that the SI unit of electric potential is a volt.

B) What are equipotential lines?

C) How are equipotential lines used to obtain the electric field lines?

Homework Answers

Answer #1

Solution)

A) We know,

[V] = [kq/r]
= [k][q]/[r]
= (N m²/C²)C/m
= N m / C

Also, we know

N m = J

Work done = Force* displacement

so [W] = J = [Fd] = [F][d] = N m
= J/C
= [Volt]

============

B) Equipotential lines lie peependicular to the electeic field.They are like contour lines on map which traces lines of equal altitude or potential.

========

C) No work is done along the equipotential surface, Hence, such movement is always perpendicular to the electeic field lines.

=====

Good luck!:)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
6-With a labelled sketch, illustrate the electric field and equipotential lines about a point charge. [2...
6-With a labelled sketch, illustrate the electric field and equipotential lines about a point charge. [2 marks] (b) A dipole, as illustrated in the following figure, consists of two charges of charge magnitude, q separated by a distance, d. Point P is separated from the dipole center by a distance, r along the x-axis. For this: i) sketch and label the electric field vector contributions at P due to the two point charges and the resultant net field vector at...
Which of the following is a correct statement? (1 point) The direction of the electric field...
Which of the following is a correct statement? (1 point) The direction of the electric field due to a negative point charge is directed away from the charge. The direction of the electric force on a positive charge is opposite to the direction of the electric field at its location. The magnitude of the electric field due to a point charge is inversely proportional to the square of the distance between the charge and the point. The unit of measurement...
1). Fill in the data table for a single positive Charge. r (m) Electric Potential (...
1). Fill in the data table for a single positive Charge. r (m) Electric Potential ( V) Electric Field ( V/m) 2). Determine the voltage ( V) vs. distance (r) relationship for a point charge.
An electron flies out of a point of an electric field, where the electric potential is...
An electron flies out of a point of an electric field, where the electric potential is 0 = 600V, with the velocity v = 1,2x10^7 m/s in the direction of the field lines. Find the electric potential in a point where the speed of the electron is zero.
An ion of mass m and charge q is accelerated by a potential difference of V...
An ion of mass m and charge q is accelerated by a potential difference of V and allowed to enter a magnetic field B. In the field it moves in a semi-circle, striking photographic plate at a distance x from the slit. Show that the mass of the ion is given by ?=(?^2??^2) /8?.
The electric potential in an electric field is given by V(x, y, z)= (-9.40 V/m5)x3y2 +...
The electric potential in an electric field is given by V(x, y, z)= (-9.40 V/m5)x3y2 + (3.85 V/m4)y4 - (9.8 V/m2)zy. Determine the unit vector form E = [ Ex V/m)i + (Ey V/m)j + (Ez V/m)k] of the electric field at the point whose coordinates are (-1.3 m, 2.3 m, 3.1 m). Give the x, y, z components of electric field in the form "+/-abc" V/m, or, "ab.c" V/m as is appropriate. For example, if you calculate the electric...
Drag a negative charge onto the grid and use the tape measure to place this charge...
Drag a negative charge onto the grid and use the tape measure to place this charge 0.5 m directly to the right of the positive charge. Drag a Voltmeter back onto the grid. Use the tape measure and the sensor to measure the electric potential at a distance of 0.5 m directly above the negative charge. Record below. V=___5.760V______           Use what we’ve learned in class to calculate the electric potential at this location. Show all work below. ( 1nC =...
Suppose that a negative charge distribution of in space presents the following expression for electric potential...
Suppose that a negative charge distribution of in space presents the following expression for electric potential as a function of radius: V(r)=-k*Q/(r^3-1) If the charge distribution Q = 1 C. The electrostatic force that a proton would feel (q = 1.6x10-19 C) at a 'r' of 1 x10-9 m distance is: (Use the relationship between electric potential and electric field, followed by the relationship between electric field and electrostatic force) Response options group F = + 4.315 x 10 ^...
The electric potential (V) at a certain point in space is given by: V(x, y, z)...
The electric potential (V) at a certain point in space is given by: V(x, y, z) = 5x2-3xy+xyz a) find the directional derivative of the potential at P(3,4,5) in the direction of the vector v=i+j+k b) calculate the gradient of the electric potential
Immediately outside a conducting sphere of unknown charge Q and radius R the electric potential is...
Immediately outside a conducting sphere of unknown charge Q and radius R the electric potential is 190 V, and 10.0 cm further from the sphere, the potential is 130 V. (a) Determine the radius R of the sphere (in cm). cm (b) Determine the charge Q on the sphere (in nC). nC (c) The electric potential immediately outside another charged conducting sphere is 220 V, and 10.0 cm farther from the center the magnitude of the electric field is 410...