We are going to solve the given problem using conservation of energy principle. According to which, the total energy of a isolated system remains constant.
Now, the total energy given to the rocket,
E= Work done by the rocket=25000 Joules (given)
Now, the potential energy of the rocket of mass 'm' at a height 'h' is
Acceleration due to gravity
And the kinetic energy of the rocket at velocity 'v' is
So, according to conservation of mechanical energy,
Now, given m=5kg
(A)
At height, ,
(B)
When the rocket hits the ground, h=0.
(C)
If the rocket is lunched straight up, at the maximum height, velocity
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