Question

I ONLY HAVE ONE TRY LEFT. PLEASE BE RIGHT. ITS NOT A,E or F

Select from the following for the next question:

A	virtual, upright and smaller than the object
B	real, inverted and larger than the object
C	real, upright and smaller than the object
D	real, upright and larger than the object
E	virtual, upright and larger than the object
F	virtual, inverted and larger than the object
G	virtual, inverted and smaller than the object
H	real, inverted and smaller than the object

A B C D E F G H  An object is placed 38.3 cm away from a converging lens. The lens has a focal length of 10.0 cm. Select the statement from the list above which best describes the image.

Answer 1

Using the Lens equation :

1/v + 1/u = 1/f

here,

v = image distance

u = object distance = 38.3 cm

f = focal length = 10 cm

So,

1/v + 1/38.3 = 1/10

So, v = 13.5 cm

As the object is placed beyond twice the focal length (= 2*10 cm = 20 cm), the image will be placed between f(10 cm) and 2f ( 20cm ) on the opposite side of the lens. So, the image is real and inverted . Also, as v is less than u so, the image is smaller than the object.

So, answer is :

H:	real, inverted and smaller than the object