Question

A tank whose bottom is a mirror is filled with water to a depth of 19.0 cm . A small fish floats motionless 6.30 cm under the surface of the water.

**Part A**

What is the apparent depth of the fish when viewed at normal incidence to the water?

Express your answer in centimeters. Use 1.33 for the index of refraction of water.

**Part B**

What is the apparent depth of the reflection of the fish in the bottom of the tank when viewed at normal incidence?

Express your answer in centimeters. Use 1.33 for the index of refraction of water.

Answer #1

A )

The apparent depth of the fish is calculated by using the relation,

d2 = 1/1.33 *6.30 cm =**4.73684211 centimeters
answer**

B)

Step 2 of 2

Calculate the apparent depth of the reflection of the fish in the bottom of the tank.

The actual depth of the reflection of the fish in the bottom of the tank is given as,

*d*1′=2(19.0cm)−6.30cm=**31.7cm**

The apparent depth of the reflection of the fish in the bottom of the tank is given as,

*d*2′ = 1/1.33*31.7 = **23.8345865 cm
answer**

let me know in a comment if there is any problem or doubts

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