Question

A tuning fork oscillates at a frequency of 441 Hzand the tip of each prong moves 1.6 mm to either side of center.

a)Calculate the maximum speed.

b)Calculate the maximum acceleration of the tip of a prong.

Answer #1

a)

f = 441 Hz

A = 1.6 x 10^{-3} m

V_{max} = Aω

=A(2πf)

= (1.6
x10^{-3})(2)(π)(441)

=4.433

V_{max} = 4.43 m/s

b)

A_{max} = Aω^{2}

=(A)(2πf)^{2}

= [1.6
x10^{-3} x (2π x 441)^{2}]

=12284.48

A_{max} = 1.22 x 10^{4}

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