A tuning fork oscillates at a frequency of 441 Hzand the tip of each prong moves 1.6 mm to either side of center.
a)Calculate the maximum speed.
b)Calculate the maximum acceleration of the tip of a prong.
a)
f = 441 Hz
A = 1.6 x 10-3 m
Vmax = Aω
=A(2πf)
= (1.6 x10-3)(2)(π)(441)
=4.433
Vmax = 4.43 m/s
b)
Amax = Aω2
=(A)(2πf)2
= [1.6 x10-3 x (2π x 441)2]
=12284.48
Amax = 1.22 x 104
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